Answer:
Step-by-step explanation:
This are similar triangle
<ABD = <ACE
CE/BD = AE/AD
33/11 = 15/AD
Let AD be x
33/11 = 15/x
Cross multiply
33x = 11×15
33x = 165
x = 165/33
x = 5
AE = AD + DE
AE = 15, AD = x = 5 and DE = y
: 15 = 5 + y
y = 15 - 5
y = 10
BD/CE = AB/AC
11/33 = 9/(x+9)
Cross multiply
11(x+9) = 9(33)
11x + 99 = 297
11x = 297 - 99
11x = 198
x = 198/11
x = 18
