Question

The radius of a hydrogen atom is 37pm and its mass is 1.67*10^-24g.

What is the density of the atom in grams per cubic cm.

Assume the atom is a sphere with volume (4/3)(3.14)(r^3)
PLEASE EXPLAIN HOW YOU GET THIS IF POSSIBLE!:)

Answer 1

Answer:

V = 4/3 * 3.1416 * (37x10-10)3

V = 2.12x10-25 cm3

d = m/V

d = 1.67x10-24 / 2.12x10-25 = 7.87 g/cm3

The difference in temperature, let's convert F to ºC:

ºC = -80-32/1.8 = -62.22 ºC

dT = -92.6 + 62.2 = -30.4 ºC

Answer 2

Answer:

7.890

Explanation:

Because the mass of the atom + the atomic number