mili101405 mili101405
  • 31-01-2020
  • Mathematics
contestada

how do you solve 10+5(3x-4)=2x+7

Respuesta :

frika
frika frika
  • 05-02-2020

Answer:

[tex]x=1\dfrac{4}{13}[/tex]

Step-by-step explanation:

Given the equation

[tex]10+5(3x-4)=2x+7[/tex]

Use distributive property:

[tex]10+5\cdot 3x-5\cdot 4=2x+7\\ \\10+15x-20=2x+7[/tex]

Use commutative property to rewrite the equation:

[tex]15x+10-20=2x+7[/tex]

[tex]15x-10=2x+7[/tex]

Add 10 th both sides:

[tex]15x-10+10=2x+7+10\\ \\15x=2x+17[/tex]

Subtract [tex]2x:[/tex]

[tex]15x-2x=2x+17-2x\\ \\13x=17[/tex]

Divide by 13:

[tex]x=\dfrac{17}{13}=1\dfrac{4}{13}[/tex]

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