Respuesta :
The question is incomplete, here is the complete question:
The flask contains 10.0 mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.130 M NaOH. It requires 32.4 mL of the NaOH solution to reach the end point of the titration. What is the concentration of HCl ?
Answer: The concentration of HCl is 0.421 M
Explanation:
To calculate the concentration of acid, we use the equation given by neutralization reaction:
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is HCl
[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is NaOH.
We are given:
[tex]n_1=1\\M_1=?M\\V_1=10.0mL\\n_2=1\\M_2=0.130M\\V_2=32.4mL[/tex]
Putting values in above equation, we get:
[tex]1\times M_1\times 10.0=1\times 0.130\times 32.4\\\\M_1=\frac{1\times 0.130\times 32.4}{1\times 10.0}=0.421M[/tex]
Hence, the concentration of HCl is 0.421 M
The concentration of HCl that has been titrated against NaOH has been 0.4212 M.
The titration of HCl against NaOH will result in the formation of a salt. The indicator phenolphthalein helps in the identification of the endpoint by the change in the color of the solution from pink to colorless.
The concentration of NaOH can be calculated as:
[tex]\rm M_1V_1\'=\;M_2V_2[/tex]
Where M1 has been the molarity of the HCl solution, and V1 is the volume of HCl solution.
M2 has been the molarity of NaOH solution, and V2 has been the volume of NaOH solution.
V1 = 10 ml
M2 = 0.13 M
V2 = 32.4 ml
The molarity of HCl (M1) has been:
M1 [tex]\times[/tex] 10 ml = 0.13 M [tex]\times[/tex] 32.4 ml
M1 = 0.4212 M.
Thus, the concentration of HCl that has been titrated against NaOH has been 0.4212 M.
For more information about the concentration of solution, refer to the link:
https://brainly.com/question/202460
