Answer:
Step-by-step explanation:
Given that a math exam has 44 multiple choice questions, each with choices a to d.
A student answers just by guessing. So no of questions he answers X is binomial with constant probability 1/4 = 0.25
We can find probabibility using binomial as
P(X=12) =[tex]44C12 (0.25)^{12} (0.75)^{32} \\=0.1263[/tex]
If approximated to normal we have
mean = np = 11
Std dev = [tex]\sqrt{npq} \\=2.873[/tex]
With continuity correction we get
P(X<12)
=P(X<11.5)
=0.5691