Respuesta :
Answer:
2.48 atm
Explanation:
The partial pressure of the gas is equal to the product of the mole fraction and total pressure.
So,
[tex]P_{gas}=X_{gas}\times P[/tex]
Given that:-
Moles of A = 1.33 moles
Moles of B = 2.14 moles
Moles of C = 1.12 moles
Mole fraction of B can be calculated as:-
[tex]X_B=\frac{n_B}{n_A+n_B+n_C}=\frac{2.14}{1.33+2.14+1.12}=0.47[/tex]
Total pressure = 5.28 atm
Thus, partial pressure of gas B = 0.47 x 5.28 atm = 2.48 atm
Answer:
The partial pressure of gas B is 2.46 atm
Explanation:
Step 1: Data given
moles of gas A = 1.33 moles
moles of gas B = 2.14 moles
moles of gas C = 1.12 mol
Total pressure = 5.28 atm
Step 2: Calculate the total number of moles
Total moles = moles gas A + moles gas B + moles gas C
Total moles = 1.33 + 2.14 + 1.12
Total moles = 4.59
Step 3: Calculate mol fraction
mol fraction gas A = 1.33 / 4.59 = 0.290
mol fraction gas B = 2.14 / 4.59 = 0.466
mol fraction gas C = 1.12 / 4.59 = 0.244
Step 4: Calculate partial pressures
Partial pressure gas A = 0.290 * 5.28 atm = 1.53 atm
Partial pressure gas B = 0.466 * 5.28 atm = 2.46 atm
Partial pressure gas C = 0.244 * 5.28 atm = 1.29 atm
The partial pressure of gas B is 2.46 atm
