Answer
given,
mass of block, m = 2 Kg
spring constant, k = 315 N/m
speed of the block, v = 12 m/s
a) Amplitude of the motion
[tex]A = v \sqrt{\dfrac{k}{m}}[/tex]
[tex]A =\dfrac{12}{\sqrt{\dfrac{315}{2}}}[/tex]
A = 0.956 m
b) maximum acceleration of the block
[tex]a_{max}= A \dfrac{k}{m}[/tex]
[tex]a_{max}= 0.956\times \dfrac{315}{2}[/tex]
[tex]a_{max}= 150.57\ m/s^2[/tex]
c) maximum Force
[tex]F_{max} = m a_{max}[/tex]
[tex]F_{max} = 2\times 150.57[/tex]
[tex]F_{max} = 301.14\ N[/tex]