a 2.00 kg friction-less block is attached to an ideal spring with force constant 315 N/m.Initially, the spring is neither stretched nor compressed , but the block is moving in the negative direction at 12.0 m/s. find:-a) the amplitude.b) the maximum acceleration of the block.c) the maximum force the spring exerts on the block.

Respuesta :

Answer

given,

mass of block, m = 2 Kg

spring constant, k = 315 N/m

speed of the block, v = 12 m/s

a) Amplitude of the motion

   [tex]A = v \sqrt{\dfrac{k}{m}}[/tex]

   [tex]A =\dfrac{12}{\sqrt{\dfrac{315}{2}}}[/tex]

         A = 0.956 m

b) maximum acceleration of the block

    [tex]a_{max}= A \dfrac{k}{m}[/tex]

    [tex]a_{max}= 0.956\times \dfrac{315}{2}[/tex]

    [tex]a_{max}= 150.57\ m/s^2[/tex]

c) maximum Force

  [tex]F_{max} = m a_{max}[/tex]

  [tex]F_{max} = 2\times 150.57[/tex]

  [tex]F_{max} = 301.14\ N[/tex]

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