Answer:
3750 mph
Explanation:
From the dynamic similarity principle
R_E(model)= R_E
[tex]\frac{V_{model}\rho_{model}l_{model}}{\mu_{model}} =\frac{V\rho l}{\mu}[/tex]
we can express the fluid velocity as
[tex]V_{model}=\frac{\mu_{model}\rho V}{\mu \rho_{model}}\times\frac{l}{l_{model}}[/tex]
Now, from the table we can obtain the values of density and viscosity of at at 1000 ft altitude, and also values of dynamic viscosity and density of air at normal conditions and substitute them in previous equation.
[tex]V_{model}=\frac{3.74\times10^{-7}(1.756)(240)(20)}{3.534\times10^{-7}(2.38\times10^{-3})}[/tex]
calculating we get
V_{model}= 3750 mph