Question

What is an equation of the line that passes through the points
(8,2) and
(7,1)?

Answer 1

Answer:

Step-by-step explanation:

first, we find the slope

slope = (y2 - y1) / (x2 - x1)

(8,2)....x1 = 8 and y1 = 2

(7,1)....x2 = 7 and y2 = 1

now we sub

slope = (1 - 2) / (7 - 8) = -1/-1 = 1

y = mx + b

slope(m) = 1

use either of ur points...I will use (8,2)...x = 8 and y = 2

now we sub and find b, the y intercept

2 = 1(8) + b

2 = 8 + b

2 - 8 = b

-6 = b

so ur equation is : y = 1x - 6....or just y = x - 6 <===