Question

In a football game the kicker attempts a field goal. the ball remains in contact with the kickers foot for .05 seconds, during which the time it experiences an acceleration 340 m/s squared. the ball is launched at an angle of 51 degrees above the ground. determine the horizontal and vertical components of the launches velocity

Answer 1

Answer:

Horizontal component of velocity = 17cos(51°) = 10.7 m/s

Vertical component of velocity = 17sin(51°) = 11.4 m/s

Explanation:

Acceleration = 340 $m / s^{2}$.

time during which kickers foot is in contact with the ball = 0.05 seconds

Velocity = Acceleration $\times$ time = 340 $\times$ 0.05 = 17 m/s

Horizontal component of velocity = 17cos(51°) = 10.7 m/s

Vertical component of velocity = 17sin(51°) = 11.4 m/s