Explanation:
Formula to calculate the temperature is as follows.
[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}[/tex]
[tex]T_{2} = P_{2} \times \frac{T_{1}}{P_{1}}[/tex]
It is given that,
[tex]T_{2} = 70^{o}F \times (\frac{10.5 psi}{12.5 psi})[/tex]
[tex]T_{2} = 58.8^{o}F[/tex]
T = [tex](58.8 - 32) \times \frac{5}{9}[/tex]
= [tex]14.88 ^{o}C[/tex]
Therefore, we can conclude that a temperature of [tex]14.88 ^{o}C[/tex] would be required to deflate the football to 10.5 psi.