Respuesta :
Answer:
D. 95.0kW
Explanation:
Temperature of heat supplied = 1000°C
Temperature of waste heat = 50°C
Temperature of maximum power produced = 1000°C - 50°C = 950°C
Rate of heat supplied = 100kJ/s = 100kW
Maximum power produced = 950°C/1000°C × 100kW = 95kW
The maximum power this heat engine can produce is 74.6 kW.
What is a heat engine?
In the engineering field, heat energy helps to convert heat energy to mechanical energy.
From the parameters given:
- Temperature from the source [tex]\mathbf{T_H = 1000^0 C}[/tex] = 1273 K
- The temperature in the sink [tex]\mathbf{T_L = 50 ^0 C}[/tex] = 323 K
- The heat supplied to the engine [tex]\mathbf{Q_H = 100 \ kJ/s}[/tex]
From the above information, we can determine the maximum possible efficiency for the heat engine by using the Carnot efficiency.
[tex]\mathbf{\eta_{rev}= 1 -\dfrac{T_L}{T_H} }[/tex]
[tex]\mathbf{\eta_{rev}= 1 -\dfrac{323}{1273} }[/tex]
[tex]\mathbf{\eta_{rev}= 0.746 }[/tex]
From the efficiency formula, we can determine the maximum power of the heat engine.
i.e.
[tex]\mathbf{\eta_{rev} = \dfrac{W_{in}}{Q_H}}[/tex]
[tex]\mathbf{ W_{in} =\eta_{rev} \times {Q_H}}[/tex]
[tex]\mathbf{ W_{in} =0.746 \times(100) \ kJ/s}[/tex]
[tex]\mathbf{ W_{in} =74.6 \ kJ/s}[/tex]
[tex]\mathbf{ W_{in} =74.6 \ kW}[/tex]
Therefore, we can conclude that the maximum power this heat engine can produce is 74.6 kW.
Learn more about heat engines here:
https://brainly.com/question/24707911