Answer:
[tex]v_{avg} = 5.33\ Km/h[/tex]
Explanation:
given,
motion of polar bear
1.0 km south ; 1.0 km east ; 1.0 km north ; 1.0 km west
total time of the trip = 45 min
[tex]t = \dfrac{45}{60}\ hr[/tex]
t = 0.75 hr
total distance travel by bear = 1 + 1 + 1 + 1 = 4 km
average speed of the bear = ?
[tex]average\ speed = \dfrac{total\ distance}{total\ time}[/tex]
[tex]v_{avg} = \dfrac{4}{0.75}[/tex]
[tex]v_{avg} = 5.33\ Km/h[/tex]
hence, the average speed of the car is equal to 5.33 Km/h