Answer:
2Al + 6H2O --> 2Al(H2O)3 + 3H2
Explanation:
aAl + bH2O --> cAl(H2O)3 + dH2
To balance this equation, the Al(H2O)3 is first multiplied by c = 2 to even out the water molecule.
Since we have done that, the reactant water molecule is balenced with b = 3 so that the difference in the Hydrogen in the aluminum hydroxide molecule and the reactant water molecule, which is 6 goes to the H2 (d = 3) in the product.
Then, the Al metal is balanced with a = 2 and then the reaction is balanced.
2Al + 6H2O --> 2Al(H2O) + 3H2