Question

Y=4-x2 what is the positive zero of this polynomial

Answer 1

Answer:

The positive zero is x=2

Step-by-step explanation:

we know that

The x-intercepts or zeros of the polynomial are the values of x when the value of y is equal to zero

we have

$y=4-x^{2}$

so

For y=0

$0=4-x^{2}$

solve for x

$x^2=4\\x=\pm2$

so

The zeros of the polynomial are x=-2 and x=2

therefore

The positive zero is x=2