Question

A transverse wave is traveling through a canal. If the distance between two successive crests is 3.17 m and four crests of the wave pass a buoy along the direction of travel every 22.6 s, determine the following.

(a) frequency of the wave
1 Hz

(b) speed at which the wave is traveling through the canal
2 m/s

Answer 1

Answer:

a. 0.18Hz

b. 0.56m/s

Explanation:

From the question we can deduct the following parameters

The wavelength, λ is define as the distance between two successful crest or trough and from the question we conclude that wavelength is 3.17m.

Also the period of the wave T can be computed as

T=22.6/4

T=5.65secs.

a. To compute the frequency, recall that frequency, F=1/period.

Hence,

F=1/5.65

F=0.18Hz

b. Next we compute the wave speed.

Wave speed=frequency *wavelength

Wave speed =0.18*3.17

Wave speed =0.56m/s

Answer 2

The frequency of the wave 1 Hz and the speed at which the wave is traveling through the canal 2 m/sis mathematically given as

• F=0.18Hz
• Ws=0.56m/s

What is the frequency of the wave 1 Hz and the speed at which the wave is traveling through the canal 2 m/s?

Question Parameter(s):

If the distance between two successive crests is 3.17 m

Four crests of the wave pass a buoy along the direction of travel every 22.6 s

Generally, the equation for the frequency is mathematically given as

F=1/period.

Therefore

F=1/5.65

F=0.18Hz

In conclusion, Wave speed=f *wavelength

Ws =0.18*3.17

Ws=0.56m/s

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