Question

If p(x) = x2 – 1 and q (x) = 5 (x minus 1), which expression is equivalent to (p – q)(x)?
5(x – 1) – x2 – 1
(5x – 1) – (x2 – 1)
(x2 – 1) – 5(x – 1)
(x2 – 1) – 5x – 1

Answer 1

Answer:

(x²-1) - 5(x-1).

Step-by-step explanation:

p(x) = x²-1 q(x) = 5(x-1)

(p-q) (x) = (x²-1) - 5(x-1).

Answer 2

Answer:

(x²-1) - 5(x-1).

Step-by-step explanation:

edg 2020