Question

PLEASE HELP!!!


Joe tracked the height of his Dalmatian puppy from age 13 weeks to 25 weeks. He graphed the data and determined the line of best fit is y = 1.12x + 28.78 where x is the age in weeks and y is the height in centimeters.
How old was the puppy when he was 54 centimeters tall? Round to the nearest tenth.
A. 22.5 weeks
B. 28.2
C. 73.9
D. 89.3


A baseball coach would like to be able to predict the number of hits his players will get based on the number of times they are at bat. He graphs some data and determines the line of best fit. The equation of the line of best fit is y= 0.32x - 20.51, where x is the number of times at bat and y is the number of hits.
How many hits should he expect from a player who is at bat 175 times? Round your answer to the nearest whole number.


A. 35
B. 37
C. 76
D. 77

Answer 1

Answer:

Question 1:

(A) 22.5 weeks

Question 2:

(A) 35

Step-by-step explanation:

Question 1:

Given:

The line of best fit is given as:

$y=1.12x+28.78$

Where,

$x\to age\ in\ weeks\\\\y\to height\ in\ centimeters$

Height of the puppy (y) = 54 cm

Now, plug in the value of 'y' and solve for 'x'. This gives,

$54=1.12x+28.78\\\\54-28.78=1.12x\\\\25.22=1.12x\\\\x=\frac{25.22}{1.12}=22.5\ weeks$

Therefore, the puppy was 22.5 weeks old when he was 54 cm tall.

Question 2:

The line of best fit is given as:

$y=0.32x-20.51$

Where,

$x\to number\ of\ times\ at\ bat\\\\y\to number\ of\ hits$

Number of times at bat (x) = 175

Now, plug in the value of 'x' and solve for 'y'. This gives,

$y=0.32\times 175-20.51=35.49\approx 35$

Therefore, the number of hits is 35 to the nearest whole number.

Answer 2

Joe tracked the height of his Dalmatian puppy from age 13 weeks to 25 weeks,According to the question,  

(1) the puppy when 54 centimeters tall he was 22.5 weeks old

(2) the total number of hits should he expect from a player who is at bat 175 times is 35.

PART (A):-

Given :  $\rm y=1.12x+28.78$ where,

             $\rm x=Age\;of\;Puppy \\y= Height \;of\;Puppy$

             y = 54cm

Now, we will put the value of y in the given equation & solve for x we will get,

               $\rm 54=1.12x+28.78\\\\54-28.78 =1.12x\\\\25.22=1.12x\\\\x=\dfrac{25.22}{1.12}\\\\\rm x=22.5 weeks$

Therefore, the puppy when 54 centimeters tall he was 22.5 weeks old

PART(B):-

Given :   $\rm y=0.32x-20.51$ where,

             $\rm x = number \;of \;times \;at\; bat.\\\rm y= Number\; of \;hit$

             x = 175

Now, we will put the value of x in the given equation & solve for y we will get,

                 $\rm y=0.32\times175-20.51\\\\y=35.49 \approx 35\\\\y = 35$

Therefore, the total number of hits should he expect from a player who is at bat 175 times is 35.

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