Respuesta :
We have this table
[tex]\begin{array}{|c|c|c|c|c|}\cline{1-5}\text{outcome}&A&B&C&D\\ \cline{1-5}\text{frequency}&20&11&14&30\\ \cline{1-5} \end{array} \\[/tex]
The values in the bottom row add to 20+11+14+30 = 75, so that matches up with the fact that the spinner was spun 75 times. Of those 75 spins, 11+14 = 25 landed on either B or C.
So 25/75 = 0.33 is the approximate experimental probability of landing on B or C.
Answer: Choice A) 0.33
The experimental probability of spinning B or C is option a. 0.33. This is obtained by applying probability for mutually exclusive events.
Probability:
- Probability is the measure of the likelihood of an event to occur.
- Probability is given by the ratio of the number of favorable outcomes to the total number of outcomes
- [tex]P(A)=\frac{n(A)}{n(B)}[/tex] Where n(A)-number of favorable outcomes of event A and n(S)-total number of possible outcomes.
Mutually exclusive events:
- Two or more events that cannot be happened simultaneously are said to be mutually exclusive events.
- If X and Y are mutually exclusive events then the probability of X or Y is P(X or Y)=P(X)+P(Y).
Calculating the probability for given data:
Given that,
The spinner is spun 75 times.
Outcomes - A, B, C, D
Frequency - 20, 11, 14, 30 respectively
The probability of spinning B is [tex]P(B)=\frac{11}{75}[/tex] and
The probability of spinning C is [tex]P(B)=\frac{14}{75}[/tex]
Since B and C cannot exist at the same time, they are mutually exclusive.
So,
P(B or C)=P(B)+P(C)
⇒ P(B or C) = [tex]\frac{11}{75}+\frac{14}{75}[/tex]
⇒ P(B or C) = [tex]\frac{25}{75}[/tex]
⇒ P(B or C) = 0.3333...
Rounding off to the nearest hundredth,
⇒ P(B or C) = 0.33
Therefore. option a. 0.33 is correct and it is the required probability of spinning B or C.
Learn more about mutually exclusive events here:
https://brainly.com/question/14660720
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