Answer: 2.73g of CH3CH2OH Will be consumed
Explanation:
CH3CH2OH + O2 —> CH3COOH + H2O
MM of CH3CH2OH = 12 + 3 +12 + 2 16 +1 = 46g/mol
MM of O2 = 16 x2 = 32
Mass conc. Of O2 = 1.9g
From the equation,
32g of O2 consumed 46g of CH3CH2OH .
Therefore, 1.9g of O2 will consume Xg of CH3CH2OH i.e
Xg of CH3CH2OH = (1.9 x 46)/32 = 2.73g