Answer:
260 skirts and 270 blouses are left in the store after the sale.
Step-by-step explanation:
Let x be the number of skirts and y be the number of blouses.
An apparel shop sells skirts for $45 and blouses for $35
Cost of entire stock = $51,750
Thus, we can write the equation,
[tex]45x + 35y = 51750[/tex]
Half the skirts and two-thirds of the blouses are sold for a total of $30,600.
Thus, we can write the equation,
[tex]45(\dfrac{x}{2}) + 35(\dfrac{2y}{3}) = 30600\\\\135x + 140y = 183600[/tex]
Solving the two equations by elimination method, we have,
[tex]135x + 140y-(135x + 105y) = 183600 - 155250\\35y = 28350\\\\y = \dfrac{28350}{35} =810\\\\x = \dfrac{51750-35(810)}{45} = 520[/tex]
Thus, there were 520 skirts and 810 blouses in the store.
Skirt left =
[tex]520-\dfrac{520}{2} = 260[/tex]
Blouses left =
[tex]810 - \dfrac{2}{3}\times 810 = 270[/tex]
Thus, 260 skirts and 270 blouses are left in the store after the sale.