6.3.AP-9
3 Question Help
Suppose that you have $6,000 to invest. Which investment yields the greater return over a 10 year period: 7.42% compounded daily or 7.5% compounded quarterly?
Find the total amount of the investment after 10 years if $6,000 is invested at 7.42% compounded daily.
$
(Round to the nearest cent as needed.)​

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Answer:

The investment at 7.42%; $12 599.84

Step-by-step explanation:

The formula for the amount (A) accrued on an investment earning compound interest is

[tex]A = P(1 + \frac{r}{n})^{nt}[/tex]

where

P = the amount of money invested (the principal)

r = the annual interest rate expressed as a decimal fraction

t = the time in years

n = the number of compounding periods per year

1. Daily compounding

Data:

P = $6000

r =  7.42 % = 0.0742

t = 10 yr

n = 365 /yr

Calculation:

[tex]\begin{array}{rcl}\\A& =& P \left (1 + \dfrac{r}{n} \right )^{nt}\\\\& =& 6000 \left(1 + \dfrac{0.0742}{365} \right)^{365\times10}\\\\& =& 6000 \left(1 + 0.0002032888 \right)^{365\times10}\\& =& 6000 (1.000203288)^{3650}\\& =& 6000 \times 2.0999732\\& =& \mathbf{12599.84}\\\end{array}\\[/tex]

2. Quarterly compounding

Data:

r = 7.5 % = 0.075

n = 4 /yr

Calculation:

[tex]\begin{array}{rcl}A& =& P \left (1 + \dfrac{r}{n} \right )^{nt}\\& =& 6000 \left(1 + \dfrac{0.075}{4} \right )^{4\times10}\\& =& 6000 (1 + 0.01875)^{40}\\& =& 6000 (1.01875)^{40}\\& =& 6000 \times 2.102349277\\& =& \mathbf{12614.10}\\\end{array}\\[/tex]

This investment yields the greater return, but the difference is less than $1.50 per year.

3. $ 6000 at 7.42 % compounded daily

From Part 1, the value of the investment is $12 599.84.

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