Respuesta :
Answer
a) C
b) B
c) C, E
d) 15.5
e) 0.7
f) 67.7
Step-by-step explanation
a) A linear equation can be written as [tex]y=mx+c[/tex] where [tex]m[/tex] is the slope and [tex]c[/tex] is the intercept on the [tex]y[/tex]-axis. The slope describes how [tex]y[/tex] changes when [tex]x[/tex] changes. A negative value means the it is a decreasing change. In our case, [tex]y[/tex] is [tex]A[/tex] and [tex]x[/tex] is [tex]t[/tex]. Thus, the slope of the equation is [tex]m=-0.062[/tex]. This means that the area of glacier is decreasing by [tex]0.062 \text{km}{}^2 = 62000 \text{m}{}^2[/tex] every year since 2000.
b) The [tex]A[/tex]-intercept (= 16.2 [tex]\text{km}{}^2[/tex]) represents the area covered when [tex]t=0[/tex]. But [tex]t=0[/tex] starting from year 2000. This intercept then represents the area covered by glacier in the year 2000. Therefore, the area covered by glacier in 2000 was 16.2 [tex]\text{km}{}^2[/tex].
c) [tex]A=f(t)[/tex] means the area covered after year 2000. Setting it to 12 means the area covered after [tex]t[/tex] years is 12 [tex]\text{km}{}^2[/tex]). [tex]t[/tex] is therefore the number of years since 2000 that the total area covered will be 12 [tex]\text{km}{}^2[/tex]).
d) [tex]f(12)=16.2−0.062\times12 =16.2-0.744 = =15.456 15.5 \text{km}{}^2[/tex] to 1 decimal place.
e) The term involving [tex]t[/tex] represents the disappearing area. In 12 years, the disappeared area is [tex]0.062\times12=0.744 =0.7 \text{km}{}^2[/tex] to 1 decimal place.
f) [tex]f(t)=16.2−0.062t =12[/tex]
[tex]0.062t = 16.2-12 = 4.2[/tex]
[tex]t = \dfrac{4.2}{0.062}=67.7419\ldots =67.7[/tex] years to 1 decimal place.