Question

Cairo purchased a concert ticket for $30. The cost of the ticket was 5/6 the cost of his dinner. The cost of his hotel was 3 1/2 times as much as his ticket. How much did his dinner cost?

Answer 1

Answer:

The cost of his dinner is $36.

Step-by-step explanation:

Given:

Cost of ticket = $30

Cost of ticket is 5/6 the cost of his dinner.

Cost of his hotel was 3 1/2 times as much as his ticket.

Let the cost of dinner be 'x' dollars.

As per question:

Cost of ticket = $\frac{5}{6}\times x$

⇒ $30=\dfrac{5x}{6}$

Multiplying both sides by 6, we get:

$30\times 6=\frac{5x}{6}\times 6\\\\180=5x$

Dividing both sides by 5, we get:

$\frac{180}{5}=\frac{5x}{5}\\\\36=x\ or\\\\x=36$

Therefore, the cost of his dinner is $36.