Out of 50 students taking a midterm exam 16 answered the first of two bonus questions 33 answered the second bonus question and 3 didnt bother. Whst percentage of students tried both questions?

Respuesta :

Answer:

4% of students tried both questions.

Step-by-step explanation:

Given:

Total students taking the exam = 50

Number of students who answered the first question = 16

Number of students who answered the second question = 33

Number of students who din't answer any = 3

To find the percent of students who tried both questions.

Solution:

Total students who answered at least one question = [tex]50-3 = 47[/tex]

Number of students who tried both questions can be given as :

⇒ [tex]33+16-47[/tex]

⇒ [tex]49-47[/tex]

⇒ [tex]2[/tex]

Percentage of students who tried both questions can be given as:

⇒ [tex]\frac{Number\ of\ students\ trying\ both\ questions}{Total\ number\ of\ students}\times 100[/tex]

⇒ [tex]\frac{2}{50}\times 100[/tex]

⇒ [tex]4\%[/tex]

Thus, 4% of students tried both questions.

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