To solve this problem we will apply the electrostatic Force equations defined from Coulomb's Law. In general, said force can be defined as,
[tex]F = \frac{kq_1q_2}{r^2}[/tex]
Here,
k = Coulomb's constant
[tex]q_{1,2}[/tex] = Charge
r = Distance
The electric force in B due to A is
[tex]F = \frac{kQ(-2Q)}{r^2}[/tex]
[tex]F = \frac{-2Q^2}{r^2}[/tex]
The force in A due to B is
[tex]F' = \frac{kq_1q_2}{r^2}[/tex]
[tex]F' = \frac{kQ(-2Q)}{r^2}[/tex]
[tex]F' = \frac{-2Q^2}{r^2}[/tex]
Therefore they are the same.
[tex]F' = F[/tex]
Correct option is D. F.