Question

A force of 2 Newtons will compress a spring from 1 meter (its natural length) to 0.8 meters. How much work is required to stretch the spring from 1.1 meters to 1.5 meters

Answer 1

Answer:

The work required to stretch the spring from 1.1 meters to 1.5 meters is equal to 5.2 joules

Explanation:

Given that,

Force acting on the spring, F = 2 N

The spring compresses from 1 meter (its natural length) to 0.8 meters

The force acting on the spring is given by :

$F=-kx$

$2=-k(0.8-1)$

k = 10 N/m

Let W is the work required to stretch the spring from 1.1 meters to 1.5 meters. It is given by :

$W=\dfrac{1}{2}k(x_2^2-x_1^2)$

$W=\dfrac{1}{2}\times 10\times (1.5^2-1.1^2)$

W = 5.2 Joules

So, the work required to stretch the spring from 1.1 meters to 1.5 meters is equal to 5.2 joules. Hence, this is the required solution.