Answer:
-191
Step-by-step explanation:
A limit is the value that a function approaches as the input approaches some value.
We say [tex]\displaystyle \lim_{x\rightarrow a}f(x)=L[/tex] if f(x) approaches to L as x approaches to a.
To find:[tex]\displaystyle \lim_{x\rightarrow -4}2x^3-4x^2+2x+9[/tex]
Solution:
Let [tex]f(x)=2x^3-4x^2+2x+9[/tex]
On putting x = -4 in function [tex]f(x)=2x^3-4x^2+2x+9[/tex], we get
[tex]\displaystyle \lim_{x\rightarrow -4}2x^3-4x^2+2x+9\\=2(-4)^3-4(-4)^2+2(-4)+9\\=2(-64)-4(16)-8+9\\=-128-64-8+9\\=-128-63\\=-191[/tex]
