Answer:
The probability that all four aces will be received by the same player is approximately 0.01.
Step-by-step explanation:
Of the 52 cards the four aces can be selected in [tex]52\choose4[/tex] ways.
If any one of the players receives all the four aces then that player can be selected in [tex]4\choose1[/tex] ways.
Now for the selected player to receive all the four aces, the four ace cards must be placed among the 13 cards the player receives. This can be done in [tex]13\choose4[/tex] ways.
Then the total number of ways such that all the four aces is received by one player is [tex]4[/tex] [tex]13\choose4[/tex].
Then the probability that all four aces will be received by the same player is:
[tex]4\times\frac{{13\choose4}}{{52\choose4}}=4\times\frac{715}{270725} =0.01056\approx 0.01[/tex]
Thus, the probability that all four aces will be received by the same player is approximately 0.01.