Answer:
a) 0.03
b) 0.68
c) 0.32
Step-by-step explanation:
We are given the following in the question:
B: companies in the area of biotechnology
I: companies in the area of information technology
P(B) = 0.2
P(I) = 0.15
The two events are given to be independent.
a) P(both companies become profitable)
[tex]P(B\cap I) = P(B)\times P(I)\\= 0.2\times 0.15 = 0.03[/tex]
0.03 is the probability that both companies become profitable
b) P(neither company becomes profitable)
[tex]P(B'\cap I')\\=P(B')\times P(I')\\=(1-P(B))(1-P(I))\\=(1-0.2)(1-0.15)\\=0.68[/tex]
0.68 is the probability that neither company becomes profitable.
c) P(at least one of the two companies become profitable)
[tex]P(B\cup I) = P(B) + P(I) - P(B\cap I)\\= 0.2 + 0.15 - 0.03\\=0.32[/tex]
0.32 is the probability that at least one of the two companies become profitable