jlh32900 jlh32900
  • 30-01-2020
  • Mathematics
contestada

What is the sum of the first 12 terms of the geometric series below 1/2+2+8+32+

Respuesta :

DevonFen DevonFen
  • 05-02-2020

∴[tex]\frac{1}{2} +2+8+32.......12^{th}term[/tex] =2796202.5

Step-by-step explanation:

First term(a) = [tex]\frac{1}{2}[/tex]   common ratio(r)     =[tex]\frac{2}{\frac{1}{2} }[/tex]   =4

n= 12

[tex]S_{n}=\frac{a(r^n-1)}{(r-1)}[/tex]

[tex]S_{12}=\frac{\frac{1}{2}(4^{12}-1) }{4-1}[/tex] =2796202.5

∴[tex]\frac{1}{2} +2+8+32.......12^{th}term[/tex] =2796202.5

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