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A 0.44-kg cord is stretched between two supports, 8.1 m apart. When one support is struck by a hammer, a transverse wave travels down the cord and reaches the other support in 0.82 s .What is the tension in the cord? (Express your answer to two significant figures and include the appropriate units.

Respuesta :

Answer: 9.8N

Explanation: The velocity of a sound wave (v), tension on the string (T) and mass per unit length (u) are all related by the formulae below

T = v² * u

Where T is tension in Newton (N), v is velocity of sound waves in meter per seconds (m/s) and u is mass per unit length in kilogram per meter (kg/m)

u = mass of chord / length of chord

u = 0.44/ 8.1

u = 0.1 kg/m

Velocity of sound waves (v) =length of chord / time taken for wave to travel

v = 8.1 / 0.82 = 9.9m/s

Tension is calculated below using the formula

T = v² * u

T = (9.9)² x 0.1

T= 9.8N

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