Answer:
1) q=18414.93 W
2) C=12920$
Explanation:
Given data:
pipe length L=25m
pipe diameter D=100mm =0.1 m
air temperature [tex]T_{s1}[/tex]=[tex]T_{\infty1} }[/tex]=25 °C.....= 298.15k
pipe surface temp [tex]T_{s2}[/tex]=150 °C.....=423.15k
surface emissivity e= 0.8
boiler efficiency η=0.90
natural gas price Cg=$0.02 per MJ
1) Total heat loss and radiation heat loss combined
q=[tex]q_{conv} +q_{rad}[/tex]
q=[tex]A[h(T_{s2}-T_{s1})+e[/tex]б([tex]T_{s2}[/tex]^4-[tex]T_{s1}[/tex]^4)]....... (1)
б=5.67×10^-8 W/m^2K^4 (boltzmann constant)
area A =L.Dπ=25×0.1π=7.85 m^2
putting all these values in eq (1)
q=18414.93 W
2) suppose boiler is operating non stop annual energy loss will be
E=q.t
=18414.93.3600.24.365
=5.81×10^11 J
to find furnace energy consumption
Ef =E/η
=6.46×10^5 MJ
annual cost
C=Cg. Ef
=12920$