Answer:
The answer is A. 3.5 kcal/mol
Explanation:
Δ[tex]G = Glc - Gg[/tex]
Gibb free energy for phase transition of raffinose is
Δ[tex]G =[/tex] Δ[tex]H - T[/tex]Δ[tex]S[/tex]
Δ[tex]G = (16.0kcal/mol) - [(3.15 * 102k) (5.05 * 10 - 3 kcal/k.mol)][/tex]
Δ[tex]G = 16.0kcal/mol - 1.60kcal/mol[/tex]
Δ[tex]G = 14.4kcal/mol[/tex]
[tex]Gg = Gl -[/tex]Δ[tex]G[/tex]
[tex]Gl = 17.9kcal/mol[/tex]
Δ[tex]G = 14.4kcal/mol[/tex]
Substituting value
[tex]Gg - Gl -[/tex]Δ[tex]G[/tex]
[tex]Gg = 17.9kcal/mol - 14.4kcal/mol[/tex]
Therefore,
[tex]Gg = 3.5kcal/mol[/tex]