Answer: The maximum static friction force on the sled is 46.122 Newton
Explanation:
Given Data
Mass of the sled = 53 kg
Coefficient static friction force ([tex]\mu_{S}[/tex]) = 0.0888 (No unit)
To find - the Maximum static friction force
The formula to find the Maximum static friction force [tex]F_{S}^{\max }[/tex] is
Maximum static friction force [tex]F_{S}^{\max }[/tex] = Product of coefficient of static friction force ([tex]\mu_{S}[/tex]) and normal force (η)
[tex]F_{S}^{\max }[/tex] = [tex]\mu_{S}[/tex] × η (Newton)
Formula to calculate the normal force (η) is
Normal force (η) = mass × acceleration due to gravity (Newton)
(where acceleration due to gravity has the constant value of 9.8 m/s²)
Normal force (η) = 53 × 9.8 (Newton)
Normal force (η) = 519.4 (Newton)
Maximum static friction force ( [tex]F_{S}^{\max }[/tex]) =0.0888 × 519.4 (Newton)
Maximum static friction force ([tex]F_{S}^{\max }[/tex] ) = 46.122 Newton
The maximum static friction force ( [tex]F_{S}^{\max }[/tex] ) is 46.122 Newton for the sled with mass 53 kg and coefficient of static friction force (η) 0.0888 (no unit).
