Answer:
a) [tex] C(X) =240 x +300[/tex]
b) [tex] C'(X) =\frac{240x +300}{x}= 240 +\frac{300}{x}[/tex]
Step-by-step explanation:
Part a
For this case we need to find a linear model like this one:
[tex] C(X) = m x +b[/tex]
We assume that the fixed costas are 300 per day so then the value of b = 300
[tex] C(X) = m x+300[/tex]
And then we can use the other condition [tex] C(20) = 5100[/tex]
And we can find the value for the slope like this:
[tex]5100= m (20) +300[/tex]
[tex] 4800 = 20 m[/tex]
[tex] m =\frac{4800}{20}=240[/tex]
So then the lineal model would be given by:
[tex] C(X) =240 x +300[/tex]
Part b
For this case we defined the cost per board like this:
[tex] C'(X) = C(X)/x[/tex]
So we just need to divide the function that we found on part a by x and if we do this we got:
[tex] C'(X) =\frac{240x +300}{x}= 240 +\frac{300}{x}[/tex]