Answer:
1. 3x^2 + 4x - 5 = 0
x₁ = (-2 + √19)/3
x₂ = (-2 - √19)/3
2. X^2 - 13x + 42 = 0
x₁ = 7
x₂ = 6
Step-by-step explanation:
1. Let's solve for x using the quadratic formula this way:
3x^2 + 4x - 5 = 0
x = [-4 +/- √(4² - 4 * 3 * -5)]/2 * 3
x = [-4 +/- √(16 + 60)]/6
x = [-4 +/- √76]/6
x = [-4 +/- 2√19]/6 (√76 =√4 * 19)
x = -2 +/- √19/3
x₁ = (-2 + √19)/3
x₂ = (-2 - √19)/3
2. Let's solve for x, factoring this way:
X^2 - 13x + 42 = 0
(x - 7) (x - 6) = 0
x₁ = 7
x₂ = 6
