Question

A 1900-kg car accelerates from 20 to 65 km/h on an uphill road. The car travels 180 m and the slope of the road from the horizontal is 18o. Determine the work done by the engine.

Answer 1

Answer:

1317140.14091 J

Explanation:

h = Perpendicular distance of the car from the ground = 180sin18

g = Acceleration due to gravity = 9.81 m/s²

u = Initial velocity = 20 kmph

v = Final velocity = 65 kmph

The work done by the engine is given by

$W=\dfrac{1}{2}m(v^2-u^2)+mgh\\\Rightarrow W=\dfrac{1}{2}\times 1900((\dfrac{65}{3.6})^2-(\dfrac{20}{3.6})^2)+1900\times 9.81\times 180sin18\\\Rightarrow W=1317140.14091\ J$

The work done by the engine is 1317140.14091 J