Answer:
Explanation:
17)
Given data:
mass of silver oxide = ?
Moles of HCl = 0.0250 mol
Solution:
Chemical equation:
Ag₂O + 2HCl → 2AgCl + H₂O
Now we will compare the moles of HCl with Ag₂O.
HCl : Ag₂O
2 : 1
0.0250 : 1/2×0.0250 = 0.0125 mol
Mass of silver oxide:
Mass = number of moles × molar mass
Mass = 0.0125 mol × 231.735 g/mol
Mass = 2.89 g
18)
Given data:
Moles of calcium chlorate = 7.65 mol
Mass of oxygen produced = ?
Solution:
Chemical equation:
Ca(ClO₃)₂ → CaCl₂ + 3O₂
Now we will compare the moles of Ca(ClO₃)₂ and O₂.
Ca(ClO₃)₂ : O₂
1 : 3
7.65 : 3×7.65 = 22.95 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 22.95 mol × 32 g/mol
Mass = 734.4 g
19)
Given:
Mass of barium chloride = ?
Molecules of HCl = 10.50×10²³ molecules
Solution:
Chemical equation:
Ba + 2HCl → BaCl₂ + H₂
Number of moles of HCl:
10.50×10²³ molecules × 1 mol / 6.022 ×10²³ molecules
1.74 moles
Now we will compare the moles of HCl with BaCl₂.
HCl : BaCl₂
2 : 1
1.74 : 1/2×1.74 = 0.87 mol
Mass of barium chloride:
Mass = number of moles × molar mass
Mass = 0.87 mol × 208.23 g/mol
Mass = 181.2 g
20)
Given data:
Mass of oxygen produced = ?
Number of molecules of water = 8.58 × 10²⁴ molecules
Solution:
Chemical equation:
2H₂O → 2H₂ + O₂
Number of moles of water:
8.58 × 10²⁴ molecules × 1 mol / 6.022 ×10²³ molecules
14.2 moles
Now we will compare the moles of water with oxygen.
H₂O : O₂
2 : 1
14.2 : 1/2 ×14.2 = 7.1 mol
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 7.1 mol × 32 g/mol
Mass = 227.2 g
