Question

Which equation represents a line passing through the point (-5, 1) and PARALLEL to the line given by y = 3x - 4

y -1 = -1/3 (x + 5)
y + 5 = 3(x - 1)
y + 1 = -1/3(x - 5)
y - 1 = 3(x + 5)

Answer 1

option (D)

(y-1)=3(x+5)

Step-by-step explanation:

Given the line passes through the point (-5,1) and parallel to the line

y= 3x-4

The slope of above line is = 3

Therefore the slope of the required straight line is m=3

The equation of a straight line is

$(y-y_1)=m(x-x_1)$

⇔(y-1)=3(x+5)     [ $x_1=-5$ and $y_1 =1$]