Answer:
option B 5.15
Explanation:
[tex]weak\ acid \rightleftharpoons conjugate\ base+H^+[/tex]
Henderson–Hasselbalch equation for pH is as follows:
[tex]pH=pKa+log\frac{[conjugate\ base]}{[weak\ acid]}[/tex]
Given:
[conjugate base] = [weak acid]
pH = 5.25
[tex]pH=pKa+log\frac{[conjugate\ base]}{[weak\ acid]}[/tex]
5.25 = pKa+log 1
pKa = 5.25
When acid is added, H+ concentration increases and as per Le Chatelier's principle, equilibrium shifts towards left hand side or concentration of weak acid increases and that of conjugate base decreases.
So, [tex]\frac{[conjugate\ base]}{weak\ acid}[/tex]<1
So, [tex]log\frac{[conjugate\ base]}{[weak\ acid]} =small\ negative\ value[/tex]
Therefore, pH of the solution will be slightly less than the initial.
Therefore, pH of the solution will be 5.15.
So, the correct option is option B