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An automobile with 0.260 m radius tires travels 80,000 km before wearing them out. How many revolutions do the tires make neglecting any backing up and any change in the radius due to wear?

Respuesta :

Answer:   About [tex]4.9\times10^7[/tex]

Explanation:

Given : The radius of each tire =  0.260 m

Circumference of tire = [tex]2\pi r[/tex] , where r  is radius

[tex]= 2(\dfrac{22}{7})\times (0.260)\approx1.63\ m[/tex]

The distance traveled by the automobile= 80,000 km

= 80,000, 000 m [ ∵  1 km= 1000 m]

Then , the number of revolutions made by each tire = (distance traveled) ÷ (Circumference of tire)

[tex]=\dfrac{80000000}{1.63}=49079754.6012\approx4.9\times10^{7}[/tex]

[Note : We are neglecting any backing up and any change in the radius due to wear.]

Hence, the number of  revolutions  [tex]\approx4.9\times10^{7}[/tex] .

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