Question

The decay of radioisotopes is a typical first order reaction. The half-life of carbon-14 (14C) is a radioactive isotope that decays to form stable 14N with a half-life of 5,730 yrs. Calculate the time required for 83% 14C to decay to 14N. g

Answer 1

Answer:

By emitting an electron and an electron antineutrino, one of the neutrons in the carbon-14 atom decays to a proton and the carbon-14 (half-life of 5,700 ± 40 years) decays into the stable (non-radioactive) isotope nitrogen-14.

Half-life: 5,730 ± 40 years

Names: carbon-14, C-14, radiocarbon

Isotope mass: 14.003241 u