Respuesta :
Answer:
Option B.
Step-by-step explanation:
The given function is
[tex]f(x)=\dfrac{2x}{1-x^2}[/tex]
We have find the behavior of the function f (x) as x approaches infinity.
The given function can be rewritten as
[tex]f(x)=\dfrac{2x}{x^2(\dfrac{1}{x^2}-1)}[/tex]
[tex]f(x)=\dfrac{2}{x(\dfrac{1}{x^2}-1)}[/tex]
[tex]lim_{x\rightarrow \infty}f(x)=lim_{x\rightarrow \infty}\dfrac{2}{x(\dfrac{1}{x^2}-1)}[/tex]
Apply limit.
[tex]lim_{x\rightarrow \infty}f(x)=\dfrac{2}{\infty(\dfrac{1}{\infty^2}-1)}[/tex]
[tex]lim_{x\rightarrow \infty}f(x)=0[/tex]
The graph approaches 0 as x approaches infinity.
Therefore, he correct option is B.