Question

You calibrated a different pipet and determined its volume to be 25.40 mL. You then use it to determine the density of an unknown liquid. You use a fresh clean dry beaker with an initial mass of 48.7073 g. You pull the unknown liquid up to the mark in the pipet and transfer this to the beaker. The new mass of the beaker and liquid is 77.8760 g. What is the density of the unknown liquid

Answer 1

Answer:

1148.37401575 kg/m³

Explanation:

Volume of liquid in pipet

25.4 mL

Mass of liquid

$77.8760-48.7073=29.1687\ g$

Density is given by

$\rho=\dfrac{m}{V}\\\Rightarrow \rho=\dfrac{29.1687}{25.4}\\\Rightarrow \rho=1.14837401575\ g/ml=1.14837401575\times 10^3=1148.37401575\ kg/m^3$

The density of the unknown liquid is 1148.37401575 kg/m³