Answer:
The pipe is open on both ends .
Explanation:
In a closed organ pipe the nth frequency is given as
[tex]f_n=(2n+1)\frac{v}{4L}\\[/tex]
For the (n+1) th frequency is given as
[tex]f_{n+1}=(2(n+1)+1)\frac{v}{4L}\\f_{n+1}=(2n+3)\frac{v}{4L}\\[/tex]
By taking ratios of both equations.
[tex]\frac{f_{n+1}}{f_{n}}=\frac{(2n+3)\frac{v}{4L}}{(2n+1)\frac{v}{4L}}\\\\\frac{274.3}{228.6}=\frac{2n+3}{2n+1}\\\\274.3(2n+1)=228.6(2n+3)\\n=4.5[/tex]
As n has to be integer thus this is not a closed organ pipe.
In a open organ pipe the nth frequency is given as
[tex]f_n=\frac{nv}{2L}\\[/tex]
For the (n+1) th frequency is given as
[tex]f_{n+1}=\frac{(n+1)v}{4L}[/tex]
[tex]\frac{f_{n+1}}{f_{n}}=\frac{\frac{(n+1)v}{4L}}{\frac{nv}{4L}}\\\\\frac{274.3}{228.6}=\frac{n+1}{n}\\\\274.3(n)=228.6(n+1)\\n=5.0[/tex]
As n is an integer in this case, i.e. the pipe is open at both ends.