Question

A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:

1) The year must be divisible by 4

2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400

Some example leap years are 1600, 1712, and 2016.

Write a program that takes in a year and determines whether that year is a leap year.

Ex: If the input is 1712, the output is:

1712 is a leap year.
Ex: If the input is 1913, the output is:

1913 is not a leap year.
import java.util.Scanner;

public class LabProgram {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int inputYear;
boolean isLeapYear;

isLeapYear = false;
inputYear = scnr.nextInt();

/* Type your code here. */
}
}

Answer 1

Answer:

import java.util.Scanner;

public class LabProgram {

   public static void main(String[] args) {

       Scanner scnr = new Scanner(System.in);

       int inputYear;

       boolean isLeapYear;

       isLeapYear = false;

       inputYear = scnr.nextInt();

       // If a year is divisible by 400,  then it is a leap year

       if (inputYear % 400 == 0)

           isLeapYear = true;

       // If a year is divisible by 100,  then it is not a leap year

       if (inputYear % 100 == 0)

           isLeapYear = false;

       // If a year is divisible by 4,  then it is a leap year

       if (inputYear % 4 == 0)

           isLeapYear = true;

       if(isLeapYear)

           System.out.println(inputYear + " is a leap year.");

       else

           System.out.println(inputYear + " is not a leap year.");

   }

}

Explanation:

If a year is divisible by 400,  then set the boolean isLeapYear to true. If a year is divisible by 100,  then set the boolean isLeapYear to false. If a year is divisible by 4,  then set the boolean isLeapYear to true.

Check if isLeapYear is true, then print that it is a leap year. Otherwise, print that it is not a leap year.

Output:

1712

1712 is a leap year.

Answer 2

Answer:

def is_leap_year(year):

  if(year % 400 == 0):

      return True

  elif year % 100 == 0:

      return False

  elif year%4 == 0:

      return True

  else:

      return False  

if __name__ == '__main__':

  n = int(input())

  if(is_leap_year(n)):

      print(n,"is a leap year.")

  else:

      print(n, "- not a leap year")

Explanation: