Answer:
The minimum diameter of the stick to bear the normal stress as 100 psi is 0.1785 in.
Explanation:
Taking moment along point A
[tex]\sum M_A=0\\F_{BC} sin 60 \times 48 -13 \times 8=0\\F_{BC}=2.502 lb_f[/tex]
Also normal stress is given as 100 psi
Now
[tex]\sigma=\frac{F}{A}\\100=\frac{2.502}{\pi \frac{d^2}{4}}\\d^2 =\frac{4 \times 2.502}{100 \pi }\\d^2=0.031856\\d=\sqrt{0.031856}\\d=0.1785 inch[/tex]
The minimum diameter of the stick to bear the normal stress as 100 psi is 0.1785 in.