A reaction at evolves of sulfur tetrafluoride gas. Calculate the volume of sulfur tetrafluoride gas that is collected. You can assume the pressure in the room is exactly . Round your answer to significant digits.

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This is an incomplete question, here is a complete question.

A reaction at 12.0 °C evolves 358 mmol of sulfur tetrafluoride gas. Calculate the volume of sulfur tetrafluoride gas that is collected. You can assume the pressure in the room is exactly 1 atm. Round your answer to 3 significant digits.

Answer : The volume of sulfur tetrafluoride gas collected is, 8.38 L

Explanation :

Using ideal gas equation :

[tex]PV=nRT[/tex]

where,

P = Pressure of gas = 1 atm

V = Volume of gas = ?

n = number of moles of gas = 358 mmol = 0.358 mol    (1 mmol = 0.001 mol)

R = Gas constant = [tex]0.0821L.atm/mol.K[/tex]

T = Temperature of gas = [tex]12.0^oC=273+12.0=285K[/tex]

Putting values in above equation, we get:

[tex]1atm\times V=0.358mole\times (0.0821L.atm/mol.K)\times 285K[/tex]

[tex]V=8.38L[/tex]

Thus, the volume of sulfur tetrafluoride gas collected is, 8.38 L

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