Question

A reaction at evolves of sulfur tetrafluoride gas. Calculate the volume of sulfur tetrafluoride gas that is collected. You can assume the pressure in the room is exactly . Round your answer to significant digits.

Answer 1

This is an incomplete question, here is a complete question.

A reaction at 12.0 °C evolves 358 mmol of sulfur tetrafluoride gas. Calculate the volume of sulfur tetrafluoride gas that is collected. You can assume the pressure in the room is exactly 1 atm. Round your answer to 3 significant digits.

Answer : The volume of sulfur tetrafluoride gas collected is, 8.38 L

Explanation :

Using ideal gas equation :

$PV=nRT$

where,

P = Pressure of gas = 1 atm

V = Volume of gas = ?

n = number of moles of gas = 358 mmol = 0.358 mol    (1 mmol = 0.001 mol)

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas = $12.0^oC=273+12.0=285K$

Putting values in above equation, we get:

$1atm\times V=0.358mole\times (0.0821L.atm/mol.K)\times 285K$

$V=8.38L$

Thus, the volume of sulfur tetrafluoride gas collected is, 8.38 L