Respuesta :

1.Area of the parallelogram= 288 square units

2.Area of the parallelogram=45 [tex]m^2[/tex]

3.Area of the trapezoid   = 34 square in.

4.Area of the trapezoid = 8 square ft

5.Area of the rhombus= 27 square cm

6.Area of the rhombus= 108 square in

7.The area of the desktop is  = 1200 square in

8.The area of the rhombus is =84 [tex]cm^2[/tex]

9.Area of the trapezoid  = 240 square ft

Step-by-step explanation:

1.

Base =16 ft and Height = 18 ft

Area of the parallelogram = base × height

                                       =16× 18 square units

                                       = 288 square units

2.

Base = 9 m and height = 5 m

Area of the parallelogram = base × height

                                        =(9×5) [tex]m^2[/tex]

                                         =45 [tex]m^2[/tex]

3 .

Height = 4 in and parallel sides are 12 in and 5 in

Area of the  trapezoid =[tex]\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height[/tex]

                            [tex]=\frac{1}{2} \times (12+5) \times 4[/tex] square in.

                             = 34 square in.

4.

Height = 2 ft  and parallel sides are 2 ft and 6 ft

Area of the trapezoid =[tex]\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height[/tex]

                              [tex]=\frac{1}{2} \times (2+6) \times 2[/tex] square ft

                              = 8 square ft

5.

Diagonals are 6 cm and 9 cm.

Area of the rhombus [tex]= \frac{1}{2}\times {\textrm{product of diagonals}[/tex]

                               [tex]=\frac{1}{2 } \times 6\times 9[/tex] square cm

                               = 27 square cm

6. Diagonals are 12 in and 18 in

Area of the rhombus [tex]= \frac{1}{2}\times {\textrm{product of diagonals}[/tex]

                               [tex]=\frac{1}{2 } \times 12\times 18[/tex] square in

                               = 108 square in

7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in

The area of the desktop is = (30 × 40 ) square in

                                            = 1200 square in

8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.

The area of the rhombus = [tex]\frac {1}{2} \times 14 \times 12[/tex] [tex]cm^2[/tex]

                                         =84 [tex]cm^2[/tex]

9.Given , the base of trapezoid are 24 ft  and 16 ft and height is 12 ft

Area of the trapezoid =[tex]\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height[/tex]

                                    = [tex]\frac{1}{2} \times (24+16) \times 12[/tex] square ft

                                     = 240 square ft

RELAXING NOICE
Relax