Plz help I'll give brainlest


Step-by-step explanation:
1.
Base =16 ft and Height = 18 ft
Area of the parallelogram = base × height
=16× 18 square units
= 288 square units
2.
Base = 9 m and height = 5 m
Area of the parallelogram = base × height
=(9×5) [tex]m^2[/tex]
=45 [tex]m^2[/tex]
3 .
Height = 4 in and parallel sides are 12 in and 5 in
Area of the trapezoid =[tex]\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height[/tex]
[tex]=\frac{1}{2} \times (12+5) \times 4[/tex] square in.
= 34 square in.
4.
Height = 2 ft and parallel sides are 2 ft and 6 ft
Area of the trapezoid =[tex]\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height[/tex]
[tex]=\frac{1}{2} \times (2+6) \times 2[/tex] square ft
= 8 square ft
5.
Diagonals are 6 cm and 9 cm.
Area of the rhombus [tex]= \frac{1}{2}\times {\textrm{product of diagonals}[/tex]
[tex]=\frac{1}{2 } \times 6\times 9[/tex] square cm
= 27 square cm
6. Diagonals are 12 in and 18 in
Area of the rhombus [tex]= \frac{1}{2}\times {\textrm{product of diagonals}[/tex]
[tex]=\frac{1}{2 } \times 12\times 18[/tex] square in
= 108 square in
7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in
The area of the desktop is = (30 × 40 ) square in
= 1200 square in
8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.
The area of the rhombus = [tex]\frac {1}{2} \times 14 \times 12[/tex] [tex]cm^2[/tex]
=84 [tex]cm^2[/tex]
9.Given , the base of trapezoid are 24 ft and 16 ft and height is 12 ft
Area of the trapezoid =[tex]\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height[/tex]
= [tex]\frac{1}{2} \times (24+16) \times 12[/tex] square ft
= 240 square ft